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Asked: May 10, 20262026-05-10T15:54:16+00:00 2026-05-10T15:54:16+00:00

Why is it wrong to use std::auto_ptr<> with standard containers?

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Why is it wrong to use std::auto_ptr<> with standard containers?

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  1. 2026-05-10T15:54:17+00:00Added an answer on May 10, 2026 at 3:54 pm

    The C++ Standard says that an STL element must be ‘copy-constructible’ and ‘assignable.’ In other words, an element must be able to be assigned or copied and the two elements are logically independent. std::auto_ptr does not fulfill this requirement.

    Take for example this code:

    class X { };  std::vector<std::auto_ptr<X> > vecX; vecX.push_back(new X);  std::auto_ptr<X> pX = vecX[0];  // vecX[0] is assigned NULL. 

    To overcome this limitation, you should use the std::unique_ptr, std::shared_ptr or std::weak_ptr smart pointers or the boost equivalents if you don’t have C++11. Here is the boost library documentation for these smart pointers.

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