Question

Why is my X method below not being called?!

static class Program {     private static void Main()     {        X((IEnumerable<int>)null);     }      public static IEnumerable<T> X<T>(IEnumerable<T> e)     {         if (e == null)             throw new ArgumentNullException();         yield break;     } } 

I tried stepping into the debugger but it doesn’t enter X! Is the yield break keyword causing some side effect I am not aware of?

If it’s worth anything, I’m using Visual Studio 2008 Express with .NET 3.5 SP1.

Answer 1

X2 is an iterator and is delayed executed. It won’t be actually run until you attempt to get a value from the returned IEnumerable instance. You can fix this to get the behavior you are actually wanting by breaking the function up into 2 parts.

   public static IEnumerable<T> X2<T>(IEnumerable<T> e)    {         if (e == null)             throw new ArgumentNullException();         return X2Helper(e);     }      private static IEnumerable<T> X2Helper<T>(IEnumerable<T> e)     {         yield break;     } 

Eric has a great blog post on this subject: http://blogs.msdn.com/ericlippert/archive/2008/09/08/high-maintenance.aspx