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Why is the answer for the below code 16? Can anybody explain the working of this program?
#define SQUARE(n) n*n
void main()
{
int j;
j =16/SQUARE(2);
printf("\n j=%d",j);
getch();
}
If we write the same code like below, then the answer is 4:
//the ans is 4 why?
#include<stdio.h>
#include<conio.h>
#define SQUARE(n) n*n
void main()
{
int j;
j =16/(SQUARE(2));
printf("\n j=%d",j);
getch();
}
you’ll get