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Home/ Questions/Q 7010453
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Editorial Team
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Editorial Team
Asked: May 27, 20262026-05-27T21:59:33+00:00 2026-05-27T21:59:33+00:00

Why is the first one able to increment pbf_[k] correctly while the second one

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Why is the first one able to increment pbf_[k] correctly while the second one does not even do it(increment)for once?

unsigned pbf_[5] ={0}; 
 bool m=0;

Code 1:

for(int k=0;k<5;k++)    
 {

  if((m=(bit_table_[k][i][bit_index ] &bit_mask[bit]))==true)    
     pbf_[k]++;
  }

Code 2:

for(int k=0;k<5;k++)    
 {
   if((bit_table_[k][i][bit_index ] & bit_mask[bit])==true)
        pbf_[k]++;
 }
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-27T21:59:34+00:00Added an answer on May 27, 2026 at 9:59 pm

    In the first case, the result of the masking is converted to bool m before it is compared to true.

    In the second case, I believe the bitmasks are some integer type. In that case true will be promoted to the same integer type (and have the value 1).

    Just remove the == true from the comparison to make them equivalent.

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