Question

Why is the following code results in error :

class A {

public:
        typedef void (A::*funptr)(void);

        void fun(void ) {
                cout << " Fun Call " <<endl;
        }

        void foo(void ) {
                cout << " Foo Call " <<endl;
        }

        funptr p[2];
        funptr q;

        A()
        {
                p[0]=&A::foo;
                p[1]=&A::fun;
                q   =&A::fun;
        }
};


int main ()
{

A obj;

(obj.*q)(void);

//(obj.p[0])();
//(obj.p[1])();

return 0;
}

Answer 1

You will need to call it like this:

(obj.*obj.q)();

The .* operator doesn’t take a member name on the right-hand side, but rather an expression that evaluates to a member pointer. When you write this:

(obj.*q)();

It is looking for a variable called q, but there is no such variable in scope.