Question

why is the result different?
If i use float it get ,675 and if i use double i get ,674… isnt that weird?

float f = 12345.6745;
double d = 12345.6745;

Locale l = Locale.forLanguageTag("es-ES");
DecimalFormat df = (DecimalFormat) NumberFormat.getInstance(l);
print(df.format(f));
>> 12.345,675

l = Locale.forLanguageTag("es-ES");
DecimalFormat df = (DecimalFormat) NumberFormat.getInstance(l);
print(df.format(d));
>> 12.345,674

Thanks

Answer 1

If i use float it get ,675 and if i use double i get ,674… isnt that weird?

Not particularly. You’re formatting different values. In particular, assuming you actually change your code so that it will compile (with an f suffix for the float), even though you’re specifying 9 digits, float will only reliably represent 7.

Neither of the numbers is exactly 12345.6745. In fact, the exact values are:

f = 12345.6748046875
d = 12345.674499999999170540831983089447021484375

Look at those and it’s obvious why the third decimal place is 5 for f and 4 for d.

If you want to preserve decimal digits, you should be considering using BigDecimal.