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Editorial Team
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Editorial Team
Asked: June 1, 20262026-06-01T11:18:08+00:00 2026-06-01T11:18:08+00:00

Why is there no list-style infinite type error when I define something like this

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Why is there no list-style infinite type error when I define something like this in Haskell (GHC)?

data Broken = Broken { title :: String,
                       loop  :: Broken }

It compiles without a type error, but clearly it’s an unusable type: I’d have to define

foo = Broken "one" (Broken "two" (Broken "three" …

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  1. Editorial Team
    Editorial Team
    2026-06-01T11:18:09+00:00Added an answer on June 1, 2026 at 11:18 am

    There’s nothing broken about it. It’s perfectly possible to define a value of that type:

    foo = Broken "one" foo
    

    Basically it’s the same thing as defining a list type that has no nil value (which is also perfectly legal). It’s perfectly possible to define values of that type, but all such values will have to be infinite.

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