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Home/ Questions/Q 8741031
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Editorial Team
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Editorial Team
Asked: June 13, 20262026-06-13T11:14:11+00:00 2026-06-13T11:14:11+00:00

Why is this code correct instance Functor IO where — note that IO isn’t

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Why is this code correct

instance Functor IO where -- note that IO isn't parametrized, and it's correct
    fmap f action = do
        result <- action
        return (f result)

but the following code has a compiler error?

class Print a where
    print :: a -> String

data A t = A t
instance Print A where  -- error: expecting one more argument to `A'
    print a = "abc"
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  1. Editorial Team
    Editorial Team
    2026-06-13T11:14:12+00:00Added an answer on June 13, 2026 at 11:14 am

    This is because the kinds don’t match. Regular types have kind *, while type constructors such as A or IO have kind * -> *, indicating that they need a type parameter in order to return a type.

    In the definition of the Print class, the compiler infers that since a is used as a plain type, it must have kind *. However, Functor works on type constructors of kind * -> *:

    class Functor f where
      fmap :: (a -> b) -> f a -> f b
    

    Here, f is not used as a plain type, but as a type constructor, so it’s inferred kind is * -> *. You can verify this with the :kind command in GHCi:

    > :kind Print
    Print :: * -> Constraint
    > :kind Functor
    Functor :: (* -> *) -> Constraint 
    
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