Question

why is this code throwing an out of memory error, when there is only 1 row in the database..

$request_db = mysql_query("SELECT * FROM requests
                WHERE haveplayed='0'") or die(mysql_error());  
                $request = mysql_fetch_array( $request_db );
                echo "<table border=\"1\" align=\"center\">";
                while ( $request['haveplayed'] == "0" ) {
                    echo "<tr><td>";
                    echo $request['SongName'];  
                    echo "</td><td>";
                    echo "<tr><td>";
                    echo $request['Artist'];    
                    echo "</td><td>";
                    echo "<tr><td>";
                    echo $request['DedicatedTo'];
                    echo "</td><td>";   
                }
                echo "</table>";

Thanks.

Answer 1

Hm, to be honest, I dont understand the use of while in this case. You are only fetching one row with this code (even if there is more then one row in the DB!). Maybe you tried something like if($request['haveplayed'] == 0) but that wouldnt make too much sense, also, as the query only returns rows with haveplayed equal 0.

As far as I can tell, you intend to output one or more rows from the requests table where haveplayed equals 0. Wouldnt it be more like this then?

$request_db = mysql_query("SELECT * FROM requests WHERE haveplayed='0'")
              or die(mysql_error());

while($request = mysql_fetch_array( $request_db )) {
    // output stuff here ...
    echo $request['SongName']; 
}