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Home/ Questions/Q 9197565
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Editorial Team
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Editorial Team
Asked: June 17, 20262026-06-17T22:06:07+00:00 2026-06-17T22:06:07+00:00

Why is this code throwing exception of unparseable date? SimpleDateFormat f = new SimpleDateFormat(yyyy-MM-dd’T’HH:mm:ss’.000Z’);

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Why is this code throwing exception of unparseable date?

SimpleDateFormat f = new SimpleDateFormat("yyyy-MM-dd'T'HH:mm:ss'.000Z'");
f.setLenient(false);
String dateStr = "2012-03-11T02:46:01.000Z";
f.parse(dateStr);

It works fine when lenient is true. It strangely works for input date ‘2012-03-01T02:46:01.000Z‘ even with lenient as false.
Default timezone being used : PST

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  1. Editorial Team
    Editorial Team
    2026-06-17T22:06:08+00:00Added an answer on June 17, 2026 at 10:06 pm

    Because that time does not exist in your default time zone—it was daylight savings time change day, and time jumped from 2:00 a.m. to 3:00 a.m., so there was no 2:46 that morning. 😛

    Since you’re parsing UTC, set the SimpleDateFormat instance time zone to UTC like so:

    f.setTimeZone(TimeZone.getTimeZone("UTC"));
    

    and your problem will go away.

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