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Home/ Questions/Q 9312823
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Editorial Team
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Editorial Team
Asked: June 19, 20262026-06-19T01:43:35+00:00 2026-06-19T01:43:35+00:00

Why is this SQL statement: select team,avg(salary) ‘Average Salary’ from orgchart group by team

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Why is this SQL statement:
select team,avg(salary) 'Average Salary' from orgchart group by team having salary <38000;

Gives the following error?

mysql> select team,avg(salary) ‘Average Salary’ from orgchart group by
team having salary <38000; ERROR 1054 (42S22): Unknown column ‘salary’
in ‘having clause’

With a group by I can only use having and not where.Correct.
The following works:

select team,avg(salary) 'Average Salary' from orgchart group by team having avg(salary)<38000;

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-19T01:43:36+00:00Added an answer on June 19, 2026 at 1:43 am

    HAVING is used to evaluate a group of rows. Prior to grouping, you can still evaluate/filter out rows individually, by applying a WHERE condition to them.

    So, in your case it should likely be

    select team, avg(salary) 'Average Salary'
    from orgchart
    where salary < 38000
    group by team;
    

    assuming that you want to calculate the average salary among the people with the salary below 38000 (separately for every team).

    However, if you are actually trying to filter out teams where the average salary is less than 38000, then having is the right choice, but you should compare avg(salary), not salary, with the given value, i.e. like this:

    select team, avg(salary) 'Average Salary'
    from orgchart
    group by team
    having avg(salary) < 38000;
    
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