Question

why its not printing ‘doub’? Looking for a detailed explanation. Thanks for your time!

#include<iostream.h>
using namespace std;

class B{
 public:
 virtual  int ft(int i) { cout <<"int"; return 0;}
};
class D: public B {
 public:
  double ft(double i){cout << "doub"; return 0.0;}
  int ft(int i) { cout <<"intdoub"; return 0;}
};

int main(){
 B *pB = new D;
 pB->ft(2.3);
}

o/p is ‘intdoub’

Answer 1

The variable pB is of type B* and does not know about the function double D::ft(double), only virtual int B::ft(int). The conversion of the double value 2.3 to int happens automatically, although you should have gotten a compiler warning.

Try:

dynamic_cast<D*>(pB)->ft(2.3);
dynamic_cast<D*>(pB)->B::ft(2.3);