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Home/ Questions/Q 9245083
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Editorial Team
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Editorial Team
Asked: June 18, 20262026-06-18T09:11:09+00:00 2026-06-18T09:11:09+00:00

Why long t = System.currentTimeMillis(); int size = 3333333; int[][][] arr = new int[size][6][2];

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Why

        long t = System.currentTimeMillis();
        int size = 3333333;
        int[][][] arr = new int[size][6][2];
//        int[][][] arr= new int[2][6][size];
        pr(System.currentTimeMillis() - t );

prints 5000 ms
but

        long t = System.currentTimeMillis();
        int size = 3333333;
//        int[][][] arr = new int[size][6][2];
        int[][][] arr= new int[2][6][size];
        pr(System.currentTimeMillis() - t );

prints 44 ms

Second solution 115 time faster

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-18T09:11:10+00:00Added an answer on June 18, 2026 at 9:11 am

    It’s simplier to test int[][]

    int[][] arr = new int[size][2];
    

    In this case you have to allocate size pieces of memory with size of 16 bytes.

    And in this case

    int[][] arr = new int[2][size];
    

    you have only to allocate 2 pieces of memory of size*8 bytes.

    And allocating is expensive operation.

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