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Home/ Questions/Q 6925809
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Editorial Team
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Editorial Team
Asked: May 27, 20262026-05-27T10:50:15+00:00 2026-05-27T10:50:15+00:00

Why this code does not compile: #include <boost/mpl/vector.hpp> #include <boost/mpl/for_each.hpp> #include <iostream> using namespace

  • 0

Why this code does not compile:

#include <boost/mpl/vector.hpp>
#include <boost/mpl/for_each.hpp>
#include <iostream>

using namespace std;
using namespace boost;

template <class T>   // specific visitor for type printing
static void print_type(T t)
    {
        std::cout << typeid(T).name() << std::endl;
    }


typedef mpl::vector<int, long, char*> s;
int main ()
{
    mpl::for_each<s>(print_type());
}

I wonder – how to make boost mpl for_each work with free functions from same class?

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  1. Editorial Team
    Editorial Team
    2026-05-27T10:50:16+00:00Added an answer on May 27, 2026 at 10:50 am

    As stated you need a functor.

    The code below includes an additional wrap template that allows the print functor to cope with references.

    #include <iostream>
    #include <typeinfo>
    #include <boost/mpl/vector.hpp>
    #include <boost/mpl/for_each.hpp>
    #include <boost/mpl/placeholders.hpp>
    
    using namespace std;
    using namespace boost;
    
    template <typename T>
    struct wrap {};
    
    struct print_type
    {
        template< typename T>
        void operator()( wrap<T> ) const
        {
            cout << typeid(T).name() << "\n";
        }
    };
    
    typedef mpl::vector<int, long&, char*> s;
    
    int main ()
    {
        mpl::for_each<s, wrap<mpl::placeholders::_1> >(print_type());
        return 0;
    }
    

    Note: this code based on examples in the book ‘C++ Template Metaprogramming by David Abrahams and Aleksy Gurtovoy

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