Question

Why this code is not displaying any output: Instead if we use

cout << &s1.f 

or

cout << &s1.i

gives the proper output.

# include <iostream>
using namespace std;

struct s
{
char c;
int i;
float f;

}s1;

int main()
{
cout << &s1.c;
}

Answer 1

There is an overload of operator<< that takes a char* and displays it as a null-terminated string. If you want to display the pointer address, cast the pointer to void*.