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Home/ Questions/Q 9143903
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Editorial Team
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Editorial Team
Asked: June 17, 20262026-06-17T10:08:17+00:00 2026-06-17T10:08:17+00:00

Why this code no raise an error? List<String> x; void main() { x =

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Why this code no raise an error?

List<String> x;

void main() {
  x = [1,23,3,423,2];
  print(x);
}

Sorry for the newbie question, but i just start learning dart, and i ask this because of my understanding that the x can only contain a list ofString and should raise an exception due to the value not a list of String but a list of num. This is a bug, or?

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  1. Editorial Team
    Editorial Team
    2026-06-17T10:08:19+00:00Added an answer on June 17, 2026 at 10:08 am

    This is optional typing in action.

    var x; // same as List<String> x
    List<String> y;
    
    main() {
      x = [1,2,3,4];
      y = x; // valid
      x = y; // valid
      print(x); // [1,2,3,4]
      print(y); // [1,2,3,4]
    }
    

    Whether you specify List<String> or var, your code will execute the same. The type annotations (List<String>) are used by the tools to verify your code.

    A good article to read on the dartlang site is one about optional types.

    Edit: Actually, this is also an interesting point about Lists. If you initialize a list using a literal list( eg, []), then you are actually creating a List(), eg:

    main() {
      var x = new List(); 
      var y = [];
      print(x is List); // true
      print(y is List); // true
    }
    

    If, however, you want a typed list using generics, you must use the constructor syntax, eg:

    main() {
      var x = new List<String>();
      print(x is List); // true
      print(x is List<String>); // true
      print(x is List<num>); // false
    }
    
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