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Home/ Questions/Q 8980065
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Editorial Team
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Editorial Team
Asked: June 15, 20262026-06-15T19:59:21+00:00 2026-06-15T19:59:21+00:00

Why this expression evaluating to 13 ?. I accidentally evaluated this expression (1_2).next instead

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Why this expression evaluating to 13 ?.

I accidentally evaluated this expression (1_2).next instead of (1+2).next which o/p 4 as result.

=> (1_2).next
=> 13

Please let me know how this is, as i m new to Ruby

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  1. Editorial Team
    Editorial Team
    2026-06-15T19:59:23+00:00Added an answer on June 15, 2026 at 7:59 pm

    Ruby allows you to use _ to break up long numbers, for example

    123456789 == 123_456_789
    

    but the latter is a little easier to read, so your code is the same as 12.next

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