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Home/ Questions/Q 6163143
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Editorial Team
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Editorial Team
Asked: May 23, 20262026-05-23T21:46:30+00:00 2026-05-23T21:46:30+00:00

Why this program will never return and continuing create child processes? int main() {

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Why this program will never return and continuing create child processes?

int main()
{
    pid_t pid;
    int foo1 = 1, foo2 = 2;
    printf("before fork()\n");

    if ((pid = vfork()) < 0 ) {
            printf("fork failed.\n");
    }else if (pid == 0) {
            foo1++;
            foo2++;
            printf("child process: pid is %d, my parent pid is  %d\n", getpid(), getppid());
    }else if (pid > 0){
            printf("parent process: pid is %d\n", getpid());
    }

    printf("%s: foo1 is %d, foo2 is %d\n",pid == 0 ? "child process" : "parent process", foo1, foo2);
    return 0;
}

the output is like:

before fork()
child process: pid is 17244, my parent pid is  15839
child process: foo1 is 2, foo2 is 3
parent process: pid is 15839
parent process: foo1 is -1079005816, foo2 is -1218256081
before fork()
child process: pid is 17245, my parent pid is  15839
child process: foo1 is 2, foo2 is 3
parent process: pid is 15839
parent process: foo1 is -1079005816, foo2 is -1218256081
before fork()
.....
.....

If add an _exit in the second if block then it’ok.
I know the vfork share the same address space with the parent process, but it is more reasonable if the progrem ends with a crash not the endless loop.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-23T21:46:31+00:00Added an answer on May 23, 2026 at 9:46 pm

    vfork is a very tricky system call and its only intended usage is to immediately have an execve in the child – for other kinds of uses it is dangerous and unpredictable.

    Also note that unlike with fork, the parent is suspended until the child exits or calls execve.

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