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Home/ Questions/Q 6573713
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Editorial Team
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Editorial Team
Asked: May 25, 20262026-05-25T15:10:07+00:00 2026-05-25T15:10:07+00:00

Why when I add an event as a function like this: function func(arg) {

  • 0

Why when I add an event as a function like this:

function func(arg) 
{
arg.style.marginLeft = "65px";
}
window.onload = function() {
var test = document.getElementById("aaa");
test.onmouseover = func(test);
}

It’s been executed immediately (even if I do not hover the element).

But this one works:

window.onload = function() {
var test = document.getElementById("aaa");
test.onmouseover = function() {
           test.style.marginLeft = "65px";
      }
}
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-25T15:10:08+00:00Added an answer on May 25, 2026 at 3:10 pm

    You’re setting the “onmouseover” property to the return value of a function call expression:

    test.onmouseover = func(test);
    

    That “func(test)” calls the function “func()”, just as it would in any other code.

    You could instead do this:

    test.onmouseover = func;
    

    That will bind the event handler and not call “func()”, but it won’t arrange for the additional parameter to be passed. edit Oh wait that’s just the DOM element itself.

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