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Home/ Questions/Q 7081125
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Editorial Team
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Editorial Team
Asked: May 28, 20262026-05-28T06:52:52+00:00 2026-05-28T06:52:52+00:00

Why when passing the code (surrounded by ”) like so: setTimeout(‘alert(James Blunt is bad)’,

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Why when passing the code (surrounded by ”) like so:

setTimeout('alert("James Blunt is bad")', 5000);

Is there the 5 second pause before showing what we all know and when passing function reference like so:

setTimeout(alert("James Blunt is bad"), 5000);

There is no pause?

http://jsfiddle.net/eBcpc/

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  1. Editorial Team
    Editorial Team
    2026-05-28T06:52:52+00:00Added an answer on May 28, 2026 at 6:52 am

    If your second example, you are not passing a function.

    You are calling alert and passing its return value (and the return value of alert is not a function).

    Function references don’t end in (…)

    setTimeout(function () { alert("Hello, world"); }, 5000);
    

    Or, with weaker browser support, pass the arguments to alert in an array as the third argument to setTimeout.:

    setTimeout(alert, 5000, ["Hello, world"]);
    
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