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Home/ Questions/Q 3807882
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Editorial Team
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Editorial Team
Asked: May 19, 20262026-05-19T15:03:40+00:00 2026-05-19T15:03:40+00:00

Why wont this work? Below code is on send.php <?php $expire=time()+60*60*24*30; $name = $_POST[‘nameField’];

  • 0

Why wont this work?

Below code is on send.php

<?php
  $expire=time()+60*60*24*30;
  $name = $_POST['nameField'];
  setcookie("name", $name, $expire);
?>

The cookie’s value is blank. Why? How do I fix this?

New question:

Why is $_POST[‘nameField’] NULL?

<form action="/contact/send.php" method="post" id="contactForm">
<input type="text" id="nameField" name="Name" value="<?php if (isset($_COOKIE["name"])){ echo $_COOKIE["name"];} ?>" class="extra_large" />
<input type="submit" class="submit" name="Submit" value="   Send   " />
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  1. Editorial Team
    Editorial Team
    2026-05-19T15:03:40+00:00Added an answer on May 19, 2026 at 3:03 pm
    <input type="text" id="nameField" name="Name"
    

    This input’s name must be nameField , too.

    <input type="text" id="nameField" name="nameField"
    

    $_GET and $_POST variables gets value of form input’s , by name. For example $_GET['stack'] and $_POST['stack'] gets <input name="stack">‘s value.

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