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Home/ Questions/Q 8260489
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Editorial Team
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Editorial Team
Asked: June 8, 20262026-06-08T03:06:41+00:00 2026-06-08T03:06:41+00:00

Why would on earth PHP convert the result of (int) ((0.1+0.7)*10) to 7, not

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Why would on earth PHP convert the result of (int) ((0.1+0.7)*10) to 7, not 8? I know that the result will be (float) 8 when it’s cast to (int) the result will be 7? Why does that happen?

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  1. Editorial Team
    Editorial Team
    2026-06-08T03:06:44+00:00Added an answer on June 8, 2026 at 3:06 am

    It is all about float. See PHP: Floating point numbers:

    Warning – Floating point precision

    Floating point numbers have limited precision. Although it depends on the system, PHP typically uses the IEEE 754 double precision format, which will give a maximum relative error due to rounding in the order of 1.11e-16. Non elementary arithmetic operations may give larger errors, and, of course, error propagation must be considered when several operations are compounded.

    Additionally, rational numbers that are exactly representable as floating point numbers in base 10, like 0.1 or 0.7, do not have an exact representation as floating point numbers in base 2, which is used internally, no matter the size of the mantissa. Hence, they cannot be converted into their internal binary counterparts without a small loss of precision. This can lead to confusing results: for example, floor((0.1+0.7)*10) will usually return 7 instead of the expected 8, since the internal representation will be something like 7.9999999999999991118….

    So never trust floating number results to the last digit, and do not compare floating point numbers directly for equality. If higher precision is necessary, the arbitrary precision math functions and gmp functions are available.

    Additional reading:

    • What Every Computer Scientist Should Know About Floating-Point Arithmetic
    • How dangerous is it to compare floating point values?
    • Why can't decimal numbers be represented exactly in binary?
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