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Home/ Questions/Q 6157329
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Editorial Team
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Editorial Team
Asked: May 23, 20262026-05-23T20:46:01+00:00 2026-05-23T20:46:01+00:00

…will it effectively become an empty try-catch in the release build? Or will it

  • 0

…will it effectively become an empty try-catch in the release build?

Or will it never make to the build?

try
{
   // do stuff...
   // do stuff...
}
catch
{
    Debugger.Break();
}

I know that Debugger calls won’t be included – obviously, but does that apply to the catch I wrapped it in, too?

And is it a bad thing? It’s just for debugging purposes – I want to see the exception right where it occurred, not where it leaves me after it bubbles up the stack. It’s just more convenient.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-23T20:46:02+00:00Added an answer on May 23, 2026 at 8:46 pm

    This will result in an empty catch-block. To avoid this you can use conditial compilation sequences:

    private void DoSomething()
    {
    #if DEBUG
        try
        {
    #endif
            //do something
    #if DEBUG
        }
        catch
        {
            Debugger.Break();
            throw;
        }
    #endif
    }
    
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