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Home/ Questions/Q 3340970
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Editorial Team
  • 0
Editorial Team
Asked: May 18, 20262026-05-18T00:40:08+00:00 2026-05-18T00:40:08+00:00

With array notation such as the following: $.each(data.feed.entry, function(i, item) { var id =

  • 0

With array notation such as the following:

$.each(data.feed.entry, function(i, item) 
{
    var id = item['id']['$t'];
});

I can retrieve the id field from a Youtube JSON feed as this string:

tag:youtube.com,2008:video:W5XpXU8TBoo

corresponding to this JSON:

entry: [

    *
      -
      {
          o
            -
            id: {
                + $t: "tag:youtube.com,2008:video:W5XpXU8TBoo"
            }

When I try to use $.parseJSON to retrieve the video value, it says this is not valid JSON:

$.each(data.feed.entry, function(i, item) 
{
    var id = item['id']['$t'];
            var video = $.parseJSON(item['id']['$t']).video;
});

Is there another way to get the video value (i.e.: W5XpXU8TBoo) from this JSON element?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-18T00:40:09+00:00Added an answer on May 18, 2026 at 12:40 am

    You can grab the video ID elsewhere in the returned object a bit simpler, like this:

    $.each(data.feed.entry, function(i, item) {
      var id = this.media$group.yt$videoid.$t;
      //use id
    });
    

    You can test it out here.

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