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Home/ Questions/Q 7897417
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Editorial Team
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Editorial Team
Asked: June 3, 20262026-06-03T08:09:40+00:00 2026-06-03T08:09:40+00:00

With C++, I struggle to understand one compilation error. I have this function, with

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With C++, I struggle to understand one compilation error.
I have this function, with this given signature:

void MethodNMMS::tryNMSA(double factor, double temperature,double& funcWorst,int& iWorst,      double& funcTry, double* funcEvals)
{
     //...
}

My question concerns argument double& functry (for instance). I call this function tryNMSA() in another function, and I would like functry to be modified during execution of this function. That is why I pass by reference.

Here is the function call:

// other initializations for funcEvals...
double funcTry = 0;
tryNMSA(-1.0,temperature,funcWorst,iWorst,&funcTry,funcEvals);

I put this ampershead because I do want to pass the thing by reference. And that is not permitted. What is wrong, why?

Thanks and regards.

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  1. Editorial Team
    Editorial Team
    2026-06-03T08:09:41+00:00Added an answer on June 3, 2026 at 8:09 am

    You should not put an ampersand there, as doing so gives a pointer, not a reference to funcTry. Getting a reference to a variable doesn’t require any special symbols or operators – just use the name of the variable.

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