Question

With my very limited knowledge of both jQuery and JS i made a small script (with the help of Nicola Peluchetti) that duplicates a tablerow when a button is clicked. This works like a charm, however, i would like to add a datepicker to it. This also works well, but just once and not on the copied fields or visa versa. It’s probably because the datepicker “thinks” there is just one field.

I found several sources to solve the problem, but again, with my newbie knowledge, it’s just to hard. I am playing with this for almost two days and can’t get it solved.

<script type='text/javascript'>//<![CDATA[ 
$(window).load(function(){
$("input[type='button'].AddRow").click(

function() {
var index = $(this).closest('tr').index();
if (index > 0) {
$(this).closest('tr').remove();
} else {
$(this).closest('tr').clone(true).prependTo($(this).closest('table'));
$(this).val(i++);
/* $('.startdatum').removeClass('hasDatepicker').datepicker({dateFormat: 'mm-dd-yy'});    */
 }

});
});//]]> 
</script>

HTML

<table width="960" border="0" align="center" cellpadding="10" cellspacing="0"     class="contentblock">
<tr>
<td width="140"><strong>Startdatum</strong></td>
<td><input name="startdatum[]" type="text" class="startdatum" value="dd/mm/jjjj" />
<script>
$(function() {
    $('.startdatum').removeClass('hasDatepicker').datepicker({
dateFormat: 'mm-dd-yy'
});
});
</script>
  <select name="locatie[]" id="locatie[]">
    <option value="" selected></option>
  </select></td>
  <td width="143"><strong>Dekking</strong></td>
  <td width="133"><select name="dekking[]" id="dekking[]">
  <option value="" selected></option>
  </select></td>
  <td width="145"><input type="Button" value="Add Row" class="AddRow"></td>
  </tr>
  </table>

Potential solutions that i don’t get:

• http://www.stemkoski.com/problem-with-jquery-ui-datepicker-dynamic-dom/
• duplicating jQuery datepicker
• Dynamic JQuery date picker code

Datepickerplugin:

• http://jqueryui.com/demos/datepicker/

Could anyone please help me out?

Answer 1

one solution is to destroy the datepickers and rebuild them after adding different ids to them. I changed your code a little:

<link rel="stylesheet" href="http://ajax.googleapis.com/ajax/libs/jqueryui/1.8.16/themes/base/jquery-ui.css" type="text/css" media="all">
<table width="960" border="0" align="center" cellpadding="10" cellspacing="0"     class="contentblock">
<tr>
<td width="140"><strong>Startdatum</strong></td>
<td><input id='datePicker' name="startdatum[]" type="text" class="startdatum" value="dd/mm/jjjj" />
  <select name="locatie[]" id="locatie[]">
    <option value="" selected></option>
  </select></td>
  <td width="143"><strong>Dekking</strong></td>
  <td width="133"><select name="dekking[]" id="dekking[]">
  <option value="" selected></option>
  </select></td>
  <td width="145"><input type="Button" value="Add Row" class="AddRow"></td>
  </tr>
  </table>

<input type="hidden" value="0" id="counter">

$('.startdatum').removeClass('hasDatepicker').datepicker({
    dateFormat: 'mm-dd-yy'
});


$("input[type='button'].AddRow").live('click',
function() {
    var index = $(this).closest('tr').index();
    if (index > 0) {
        $(this).closest('tr').remove();
    } else {


        var $tr = $(this).closest('tr').clone(true);
        var $input = $tr.find('input.startdatum');
        var index = $('input#counter').val();
        var id = 'datepicker' + index;
        index++;
        $('input#counter').val(index);
        $input.attr('id', id).data('index', index);
        console.log(index);
        $tr.prependTo($(this).closest('table'));
        $('.startdatum').each(function() {
            $(this).datepicker('destroy');
            $(this).datepicker({
                dateFormat: 'mm-dd-yy'
            });
        });

    }

});

fiddle here http://jsfiddle.net/nicolapeluchetti/87QCx/1/

Edit – if you need to attach the row after all the others:you must change

        $tr.prependTo($(this).closest('table'));

in

        $(this).closest('table').append($tr);