Question

With PHP, I’m opening a file and it looks like this:

var people = {
vikram: { time1: [ '8:00am', '8:20am', '8:40am', '9:00am',  ], time2: [ '10:20am', '10:40am', '11:00am', '11:20am',  ], time3: [ '8:00am', '8:20am', '8:40am',  ], }};

The variable I’m trying to remove will contain a time (ex. 8:00am) and I will know the timeIndex(ex. time1). I also want to keep all the other times intact.

For example, if I set the variable to 8:40am, I want the new file that is being created to look like this:

var people = {
vikram: { time1: [ '8:00am', '8:20am', '9:00am',  ], time2: [ '10:20am', '10:40am', '11:00am', '11:20am',  ], time3: [ '8:00am', '8:20am', '8:40am',  ], }};

Any help would be appreciated!

Answer 1

you can use preg_replace() for this:

<?php
$filename = 'yourfile.js';
$search = '8:40am';

$content = file_get_contents( $filename );

$pattern = '/(\s*time1:\s*\[.*)([\'"]' . 
           preg_quote($search) .
           '[\'"],?\s*)(.*\])/U';

$content = preg_replace( $pattern, '\1\3', $content ); 

file_put_contents( $filename, $content );
?>

This is a modification of the code example i answered to your last question on a similar topic.