Question

with python and regex I attempt to match repeating/overlapping patterns/blocks like

04/00127-48
U 05062012
A: SAKARK
T_ Par.: dsfsd

in

04/00127-48
U 05062012
A: SAKARK
T_ Par.: dsfsd
04/00168-42
U 05062012
A: SAKARK
T_ Par.: fdfs
04/00168-43
U 05062012
A: SAKARK
T_ Par.: fdfs

I have tried

'(?=(\d+\/.*))'

this seem to work

'((\d+\/.*?)=?\d+\/)

but is there a better approach?

Answer 1

This answers your question:

re.findall(r'.+?(?=\d\d\/|$)',s,re.DOTALL)

re.DOTALL is needed to let the . match end-of-lines.

The r in front of the regex makes it a raw string so escapes with backslash are left as they are so the regex function will handle them. It is not needed here but still a good habit for regex’s.

Your question is not very clear. Maybe this matches better what you want?

list(zip(*[iter(s.splitlines())]*4))

It gives a list with tuples.