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Home/ Questions/Q 8590919
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Editorial Team
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Editorial Team
Asked: June 11, 20262026-06-11T23:24:21+00:00 2026-06-11T23:24:21+00:00

With the below code I keep getting the error: Cannot implicitly convert type ‘System.Net.Http.MultipartFormDataStreamProvider’

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With the below code I keep getting the error: Cannot implicitly convert type ‘System.Net.Http.MultipartFormDataStreamProvider’ to ‘System.Threading.Tasks.Task>’

MultipartFormDataStreamProvider streamProvider = new MultipartFormDataStreamProvider("c:\\tmp\\uploads");

//Error line
Task<IEnumerable<HttpContent>> bodyparts =  await Request.Content.ReadAsMultipartAsync(streamProvider);

I think this is an easy one, but I’m missing it.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-11T23:24:22+00:00Added an answer on June 11, 2026 at 11:24 pm

    I ended up using this and it works great. I found it here

    http://www.asp.net/web-api/overview/working-with-http/sending-html-form-data,-part-2

    using System.Diagnostics;
    using System.Net;
    using System.Net.Http;
    using System.Threading.Tasks;
    using System.Web;
    using System.Web.Http;
    
    public class UploadController : ApiController
    {
    public async Task<HttpResponseMessage> PostFormData()
    {
        // Check if the request contains multipart/form-data.
        if (!Request.Content.IsMimeMultipartContent())
        {
            throw new HttpResponseException(HttpStatusCode.UnsupportedMediaType);
        }
    
        string root = HttpContext.Current.Server.MapPath("~/App_Data");
        var provider = new MultipartFormDataStreamProvider(root);
    
        try
        {
            // Read the form data.
            await Request.Content.ReadAsMultipartAsync(provider);
    
            // This illustrates how to get the file names.
            foreach (MultipartFileData file in provider.FileData)
            {
                Trace.WriteLine(file.Headers.ContentDisposition.FileName);
                Trace.WriteLine("Server file path: " + file.LocalFileName);
            }
            return Request.CreateResponse(HttpStatusCode.OK);
        }
        catch (System.Exception e)
        {
            return Request.CreateErrorResponse(HttpStatusCode.InternalServerError, e);
        }
    }
    

    }

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