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Editorial Team
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Asked: 2026-06-05T06:38:51+00:00

With the following jQuery code I have created a drop down that updates the

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With the following jQuery code I have created a drop down that updates the page however I believe that when it changes #content with the returned result it is counting it as a change event and pulling the #sidebar info.

<script>
var get_pages_load_options = { 
    target:        '#content',
    data: {ajaxtype: 'content'},
    beforeSubmit:  function() {
        console.debug('beforeSubmit');
    },
    success: function() {
        console.debug('successful');
    }
};
$("#content").on('change','.get_pages',function(){
    var submit_page = $(this).attr('rel');
    var form_url = $("#"+submit_page).attr('action');
    console.debug(submit_page+" & "+form_url);
    $("#"+submit_page).ajaxForm(get_pages_load_options);
    $.ajax({
        type: "POST",
        url: form_url,
        data: {ajaxtype: "side"},
        success: function(data) {
            console.debug(data);
            $("#sidebar_menu").html(data);
        }
    });
});
</script>

The HTML is as follows for #content:

<div id="content" class="content">
    <h1>Game Updates</h1>
    <form action="/gameplay/updates/" id="submit_page" name="submit_page" class="get_pages" method="post">
        <select name="year" class="get_pages" rel="submit_page">
            <option value="2012">2012 -- v1.7.0 - v2.0.0</option>
            <option value="2011">2011 -- v1.5.3 - v1.6.0</option>
            <option value="2010">2010 -- v1.3.3 - v1.5.2</option>
            <option value="2009">2009 -- v1.1.4 - v1.3.2</option>
            <option value="2008">2008 -- v0.6.0 - v1.1.3</option>
            <option value="2007">2007 -- v0.1.x - v0.5.5</option>
        </select>
    </form>
    /** Update Logs **/
    <br/><br/>
    <p>
        -----------<br />
        Thank you,<br />
        Admin deth4uall
    </p>
</div>

Do you know how I can prevent the second firing of change. Thanks!

EDIT: I do have a regular version that is default with the above supposed to be overwriting the below functionality:

$("#content").on('change','.get_pages',function(){
    var submit_page = $(this).attr('rel');
    $("#"+submit_page).submit();
});
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1 Answer

  1. Editorial Team

    If the values are undefined, simply return out of the function.

    $("#content").on('change','.get_pages',function(){
    var submit_page = $(this).attr('rel');
    var form_url = $("#"+submit_page).attr('action');
    if (!submit_page || !form_url) {
        return;
    }
    //console.debug(submit_page+" & "+form_url);
    $("#"+submit_page).ajaxForm(get_pages_load_options);
    $.ajax({
        type: "POST",
        url: form_url,
        data: {ajaxtype: "side"},
        success: function(data) {
            //console.debug(data);
            $("#sidebar_menu").html(data);
        }
    });
});
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