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Home/ Questions/Q 7746859
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Editorial Team
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Editorial Team
Asked: June 1, 20262026-06-01T10:23:15+00:00 2026-06-01T10:23:15+00:00

With the following piece of code, how do i know that anything was inserted

  • 0

With the following piece of code, how do i know that anything was inserted in to the db?

if ($stmt = $connection->prepare("insert into table (blah) values (?)")) {
$stmt->bind_param("s", $blah);  
$stmt->execute();           
$stmt->close();                                 
}

I had thought adding the following line would have worked but apparently not.

if($stmt->affected_rows==-1){$updateAdded="N"; echo "failed";}  

And then use the $updatedAdded=”N” to then skip other pieces of code further down the page that are dependent on the above insert being successful.

Any ideas?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-01T10:23:17+00:00Added an answer on June 1, 2026 at 10:23 am

    The execute() method returns a boolean … so just do this :

    if ($stmt->execute()) { 
       // it worked
    } else {
       // it didn't
    }
    

    Update: since 2022 and beyond, a failed query will throw an error Exception. So you won’t have to write any code to "skip other pieces of code further down the page" – it will be skipped automatically. Therefore you shouldn’t add any conditions and just write the code right away:

    $stmt = $connection->prepare("insert into table (blah) values (?)");
    $stmt->bind_param("s", $blah);  
    $stmt->execute();           
    

    If you need to do something in case of success, then just do it right away, like

    echo "success";
    

    You will see it only if the query was successful. Otherwise it will be the error message.

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