Question

with the following python method, I make a call to an Excel macro. I was happy when I got that to work, however I was wondering everytime I was executing this I could see a Windows temporary/lock file of the same name as the .XLA I was using the Macro from.

class XlaMakeUnmake:

    __configFile = 'xla_svn.cfg'
    __vbaTools = 'makeProtected.xla'
    __entries = {}

    def __init__(self):
        self.__readConfig()

    def __newDirs(self, dir):
        try:
            os.makedirs(dir)
        except OSError, e:
            if e.errno != errno.EEXIST:
                raise 

    ### WILL ONLY WORK FOR UNPROTECTED
    '''
    filePath: path of XLA to unmake
    outputDir: folder in which the lightweight xla and its components will be pushed to
    '''
    def unmake(self, filePath, outputDir):
        xl = win32com.client.Dispatch("Excel.Application")
        xl.Visible = 0
        self.__newDirs(outputDir)
        xl.Application.Run("'" + os.getcwd() + os.sep + self.__vbaTools +   "'!Unmake", filePath, outputDir)

When I open the task manager, I can see that an Excel process is still running… How to kill it but in a clean fashion when the job is done ? Is xl.Application.Run launching an asynchronous call to the Macro ? In which case it might be tricky…

Thanks guys !! 😉

Answer 1

I don’t know Python, but you need to use:

xl.Quit