Question

With the XElement class, its constructor clearly takes the daya type XName as its first parameter, however, if I pass in a string, it works and I don’t get a compile time error.

What’s going on here exactly and how can I implment this in my own code?

Thank you,

Answer 1

There’s an implicit conversion from string to XName, basically. That’s why this works too:

XName name = "element-name";

You can do this with your own types if you provide an appropriate implicit conversion – but generally I wouldn’t do this. (Note that you can provide the conversion either at the source type or the target type; in this case it’s the target type (XName) which provides the conversion, not the source type (string).)

LINQ to XML does all kinds of interesting things with operator and conversion overloads which would normally be a bad idea, but happen to work really well in the context of XML. I particularly like the namespace handling:

XNamespace ns = "some namespace uri";
XName fullName = ns + "element-name";

Another useful oddity is the explicit conversions from XAttribute and XElement to various types; for example you can do:

XAttribute attribute = ...;
int? value = (int?) attribute;

The beauty of the nullability here is that if attribute is null, then the result will be too. This allows you to handle optional attributes (and elements) very cleanly.