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Home/ Questions/Q 4620138
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Editorial Team
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Editorial Team
Asked: May 22, 20262026-05-22T02:31:11+00:00 2026-05-22T02:31:11+00:00

With this code I get: newContent=’asdf asdf \nOUTPUT_DIRECTORY = working\topOnly’ I’d expect it to

  • 0

With this code I get:

newContent='asdf asdf \nOUTPUT_DIRECTORY       = working\topOnly'

I’d expect it to be:

newContent='asdf asdf \nOUTPUT_DIRECTORY       = working\\topOnly'

The reg ex is stripping out a """\""" between """working""" and """topOnly""". If I do something like """valStr = 'working\\ytopOnly'""" then it works as expected.

What do I need to change in my code so that it was as expected?

import re

valStr = 'working\\topOnly'
cmdFileContent = 'asdf asdf \nOUTPUT_DIRECTORY       = asdf'
name = 'OUTPUT_DIRECTORY'

varRegEx = r"""
    (\n          #match new line
    %s            #var
    \s*           #skip white spaces
    =
    \s?)          #skip white spaces
    (.*)          #match and store rest of line
    """%name

newContent  = re.compile(varRegEx, re.VERBOSE).sub(r'\1%s'%valStr, cmdFileContent)
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  1. Editorial Team
    Editorial Team
    2026-05-22T02:31:11+00:00Added an answer on May 22, 2026 at 2:31 am

    The help for re.sub says:

    repl can be either a string or a callable; if a string, backslash escapes in it are processed.

    Since it’s doing its own layer of processing escapes, you will need another layer of escapes:

    newContent = re.compile(varRegEx, re.VERBOSE).sub(r'\1%s'%valStr.replace('\\', '\\\\'), cmdFileContent)
    
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