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Editorial Team
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Editorial Team
Asked: June 14, 20262026-06-14T18:00:42+00:00 2026-06-14T18:00:42+00:00

Within one of my Django apps, I have code that looks like this within

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Within one of my Django apps, I have code that looks like this within views.py:

import myLib

resultOne = myLib.myFunction('Some data')
resultTwo = myLib.myFunction('Some more data')
resultThree = myLib.myFunction('Even more data')

Whenever I visit the page, it takes a good minute to load. The reason is that myLib takes up a lot of memory and it is loading each time the page is loaded. I know that resultTwo and resultThree will execute quickly after resultOne has executed.

I want to preload myLib in Django so that it is stored in memory and so resultOne, resultTwo, and resultThree all execute quickly. How can I do this?

EDIT:
This may fall under the category of caching. The input that resultOne, resultTwo, and resultThree changes each time and they are run very often.

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  1. Editorial Team
    Editorial Team
    2026-06-14T18:00:43+00:00Added an answer on June 14, 2026 at 6:00 pm

    In Django, you can import it in __init__.py and access it as a variable.

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