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Home/ Questions/Q 774313
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Editorial Team
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Editorial Team
Asked: May 14, 20262026-05-14T19:06:40+00:00 2026-05-14T19:06:40+00:00

Within the container BubbleContainer I have multiple Bubble sprites. Each bubble’s graphics object (a

  • 0

Within the container “BubbleContainer” I have multiple “Bubble sprites”.
Each bubble’s graphics object (a circle) is updated on a timer event.

Let’s say I have 50 Bubble sprites and each circle’s radius should be updated with a mathematical formula. How do I organize this logic?

  1. How do I update all Bubble sprites within the BubbleContainer? (should I call a bubble.update() function or make a temporary reference to the graphics object?)

  2. Where do I put the Math logic? (as static functions?)

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  1. Editorial Team
    Editorial Team
    2026-05-14T19:06:40+00:00Added an answer on May 14, 2026 at 7:06 pm

    If I were you I would worry more on how to efficiently do the Math rather than passing the data around because there you loose a big amount of time.

    My advice on this would be:

    Do all the calculation on the BubbleContainer (or anywhere else, but in one place rather than inside each object)

    • Precalc things like Math.PI/180

    • Precalc 2 arrays/vectors of sine and
      cosine values.(It’s faster to get
      them from an array rather than
      calling Math.sin/Math.cos each time )

    • Pass the result to the Bubble sprite
      in 1 call ( as Cristi pointed out )

    • Create a function that accepts input
      parameters , does all the math and
      returns the answer.

      For each set of input( on each
      cal of this function ):

      First see if the
      answer was calculated before, if it
      was retrieve it from the answer
      dictionary.

      if not calculate it and add it to the
      answer dictionary.

      Create an entry in a dictionary that
      has the input values as the key and the
      answer as the value. This way you are
      creating a cache of answers. For
      complicated,recurring calculations with a
      relatively small number of input
      parameters(as in your situation) it’s
      faster to retrieve answer that you
      already calculated from a dictionary
      rather than doing the calculation
      again. If you’ll use an array instead of a dictionary I believe it’s going to be even faster..

    Quick example, not optimized, just to give you an idea:

    function multiply(x:int,y:int):int{ 
    
    var retValue:int; 
    
    var key:String=String(x)+String(y);
    
    if (answers[key]){ retValue=answers[key];} 
    
    else{ retValue=x*y;  answers[key]=retValue;} 
    
    return retValue;
    
    }
    
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