Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • SEARCH
  • Home
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 994915
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: May 16, 20262026-05-16T06:38:27+00:00 2026-05-16T06:38:27+00:00

(Without including any external libraries.) What’s the most efficient way to remove the extension

  • 0

(Without including any external libraries.)

What’s the most efficient way to remove the extension of a filename in Java, without assuming anything of the filename?

Some examples and expected results:

  • folder > folder
  • hello.txt > hello
  • read.me > read
  • hello.bkp.txt > hello.bkp
  • weird..name > weird.
  • .hidden > .hidden

(or should the last one be just hidden?)

Edit: The original question assumed that the input is a filename (not a file path). Since some answers are talking about file paths, such functions should also work in cases like:

  • rare.folder/hello > rare.folder/hello

This particular case is handled very well by Sylvain M’s answer.

  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-05-16T06:38:28+00:00Added an answer on May 16, 2026 at 6:38 am

    I’m going to have a stab at this that uses the two-arg version of lastIndexOf in order to remove some special-case checking code, and hopefully make the intention more readable. Credit goes to Justin ‘jinguy’ Nelson for providing the basis of this method:

    public static String removeExtention(String filePath) {
        // These first few lines the same as Justin's
        File f = new File(filePath);
    
        // if it's a directory, don't remove the extention
        if (f.isDirectory()) return filePath;
    
        String name = f.getName();
    
        // Now we know it's a file - don't need to do any special hidden
        // checking or contains() checking because of:
        final int lastPeriodPos = name.lastIndexOf('.');
        if (lastPeriodPos <= 0)
        {
            // No period after first character - return name as it was passed in
            return filePath;
        }
        else
        {
            // Remove the last period and everything after it
            File renamed = new File(f.getParent(), name.substring(0, lastPeriodPos));
            return renamed.getPath();
        }
    }
    

    To me this is clearer than special-casing hidden files and files that don’t contain a dot. It also reads clearer to what I understand your specification to be; something like “remove the last dot and everything following it, assuming it exists and is not the first character of the filename”.

    Note that this example also implies Strings as inputs and outputs. Since most of the abstraction requires File objects, it would be marginally clearer if those were the inputs and outputs as well.

    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.