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Home/ Questions/Q 8038027
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Editorial Team
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Editorial Team
Asked: June 5, 20262026-06-05T03:06:04+00:00 2026-06-05T03:06:04+00:00

Witht QtCreator set up as default when you create a widget the class for

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Witht QtCreator set up as default when you create a widget the class for it creates the form as private to the class. So you have for example something like this:

namespace Ui {
class MainWindow;
}

class MainWindow : public QMainWindow
{
    Q_OBJECT

//...

private:
    Ui::MainWindow *ui;
};

Now what I want to know is how you connect to the signals within the ui. For example if this widget was embedded into a QStackedWidget and when a button is pressed the page displayed needs to change. I would have considered connecting to the button but ui is private so I cannot.

Do I have to create signals in MainWindow and then within that connect the ‘ui’ signals to them and thus bubble up the hierarchy? Or have I missed something simple?

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  1. Editorial Team
    Editorial Team
    2026-06-05T03:06:05+00:00Added an answer on June 5, 2026 at 3:06 am

    You can’t have an unrelated object connect to signals/slots of aggregate components, even if you could it would break encapsulation and become a maintenance nightmare.

    You need to expose the signals/slots of the aggregate components by adding them to the MainWindow API, and then call the relative ui component method in the definition.

    For example, in the MainWindow definition, add:

    signals:
        void buttonClicked();
    

    And then in constructor, do:

    connect( ui->button, SIGNAL( clicked() ), this, SIGNAL( buttonClicked() ) );
    

    This way, your MainWindow class propagates signals from it’s aggregates – but finetuned to exactly how you intend the class to be used.

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