Question

Working on a simple C program I’m stuck with an if test:

int line_number = 0;
if ((line_number >= argv[2]) && (line_number <= argv[4]))

gcc says:

cp.c:25: warning: comparison between pointer and integer
cp.c:25: warning: comparison between pointer and integer

What can I do to properly check the range of lines I want to deal with?

Answer 1

Of course it doesn’t work: argv is a pointer to pointer to char.. it’s not clear what you want to do but think about that argv[2] is third parameter and argv[4] is fifth one. But they are of char* type (they are strings) so if you want to parse them as integers you should do it using the function atoi:

int value = atoi(argv[2]);

will parse int that was as third parameter and place it into variable, then you can check whatever you want.