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Asked: May 11, 20262026-05-11T08:24:01+00:00 2026-05-11T08:24:01+00:00

Working on (what should be) a simple project, taking the input from stdin and

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Working on (what should be) a simple project, taking the input from stdin and reformatting it to match the output specs. I’m just wanting to see what the experts here think of the following function that is supposed to skip k chars up to the end of the line, unless k < 0, where it will keep skipping chars until it reaches newline.

  1 #include <stdio.h>  25 int skip(int count){  26   int i;  27   int ch;  28  29   for(i = 0; count < 0 || i < count; i++){  30     ch = fgetc(stdin);  31     if(ch == EOF){  32       return -1;  33     }  34     if(ch == '\n'){  35       return 0;  36     }  37   }  38   return 1;  39 } 

(including the line numbers for reference purposes)

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  1. 2026-05-11T08:24:02+00:00Added an answer on May 11, 2026 at 8:24 am

    There’s nothing seriously wrong with this code. But to make this more robust, I would:

    1. Save the value of fgetc(stdin) to an int variable, then test it to make sure it’s a blank using isspace(), reporting an error if not. Use an int not a char because fgetc() returns EOF at end of file, which cannot fit inside a char.

    2. Another minor concern is that on modern filesystems, file sizes can be larger than INT_MAX. Instead of ‘faking’ a count value of INT_MAX when k < 0, I would change the loop test to test it explicitly.

    In summary, the main loop becomes:

    int ch; for (i = 0; k < 0 || i < k; ++i) {     ch = fgetc(stdin);     if (ch == '\n') {         return 1;     } else if (ch == EOF) {         return -1;        /* Or some error code of your choice */     } else if (!isspace(ch)) {         return -2;        /* Or some error code of your choice */     } } 
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