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Asked: May 10, 20262026-05-10T18:39:11+00:00 2026-05-10T18:39:11+00:00

Would there a more elegant way of writing the following syntax? Thread t0 =

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Would there a more elegant way of writing the following syntax?

        Thread t0 = new Thread(new ParameterizedThreadStart(doWork));         t0.Start('someVal');         t0.Join();          Thread t1 = new Thread(new ParameterizedThreadStart(doWork));         t1.Start('someDiffVal');         t1.Join(); 

Presuming we want to pass 20 different values, what would the best way of setting this up be? Looping through and joining at the end?

If a new thread isn’t instantiated (like below), it errors that the thread can’t be restarted. For example:

        Thread t1 = new Thread(new ParameterizedThreadStart(doWork));         t1.Start('someVal');         t1.Start('someDiffVal'); 
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  1. 2026-05-10T18:39:12+00:00Added an answer on May 10, 2026 at 6:39 pm

    Why would you start a thread and then join against it immediately?

    I’d normally do something like this:

    List<Thread> threads = new List<Thread>();  foreach (string item in items) {     string copy = item; // Important due to variable capture     ThreadStart ts = () => DoWork(copy); // Strongly typed :)     Thread t = new Thread(ts);     t.Start();     threads.Add(t); }  foreach (Thread t in threads) {     t.Join(); } 
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