Question

Write C/C++/Java code to convert given number into words.

eg:-
Input:
1234

Output:
One thousand two hundred thirty-four.

Input:
10

Output:
Ten

Does it require a complete switch case for digits 0 to 10.

Adding “teen” after every number name (eg: 14: four “teen”.) from 14 to 19.

And than adding “ty” and the digits name for a number in the range 20 to 99.

And so on.

I think there must be some far better approach for solving this.

C code is preferred.

Answer 1

#include<iostream>
using namespace std;
void expand(int);
int main()
{
    int num;
    cout<<"Enter a number : ";
    cin>>num;
    expand(num);
}
void expand(int value)
{
    const char * const ones[20] = {"zero", "one", "two", "three","four","five","six","seven",
    "eight","nine","ten","eleven","twelve","thirteen","fourteen","fifteen","sixteen","seventeen",
    "eighteen","nineteen"};
    const char * const tens[10] = {"", "ten", "twenty", "thirty","forty","fifty","sixty","seventy",
    "eighty","ninety"};

    if(value<0)
    {
        cout<<"minus ";
        expand(-value);
    }
    else if(value>=1000)
    {
        expand(value/1000);
        cout<<" thousand";
        if(value % 1000)
        {
            if(value % 1000 < 100)
            {
                cout << " and";
            }
            cout << " " ;
            expand(value % 1000);
        }
    }
    else if(value >= 100)
    {
        expand(value / 100);
        cout<<" hundred";
        if(value % 100)
        {
            cout << " and ";
            expand (value % 100);
        }
    }
    else if(value >= 20)
    {
        cout << tens[value / 10];
        if(value % 10)
        {
            cout << " ";
            expand(value % 10);
        }
    }
    else
    {
        cout<<ones[value];
    }
    return;
}