x = 1;
std::cout << ((++x)+(++x)+(++x));
I expect the output to be 11, but it’s actually 12. Why?
x = 1; std::cout << ((++x)+(++x)+(++x)); I expect the output to be 11 ,
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x = 1;
std::cout << ((++x)+(++x)+(++x));
I expect the output to be 11, but it’s actually 12. Why?
We explain it by expecting undefined behaviour rather than any particular result. As the expression attempts to modify x multiple times without an intervening sequence point its behaviour is undefined.