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Home/ Questions/Q 979729
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Editorial Team
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Editorial Team
Asked: May 16, 20262026-05-16T04:15:52+00:00 2026-05-16T04:15:52+00:00

<xhtml:li> content1content1content1content1content1content1content1content1 <xhtml:a href=234455 doc.type=mt>titlex</xhtml:a> XXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXX <xhtml:a href=23452345#23556::ah_234555 doc.type=xx>ZZZZZZZZZZZZZZZZ</xhtml:a> </xhtml:li> Hi, From the above

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<xhtml:li>
  content1content1content1content1content1content1content1content1
  <xhtml:a href="234455" doc.type="mt">titlex</xhtml:a> 
  XXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXX
  <xhtml:a href="23452345#23556::ah_234555" doc.type="xx">ZZZZZZZZZZZZZZZZ</xhtml:a> 
  </xhtml:li>

Hi,

From the above xml how to extract the text “xxx…”. I am able to take content1… and also process other tags but how to get xxxx ?

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  1. Editorial Team
    Editorial Team
    2026-05-16T04:15:52+00:00Added an answer on May 16, 2026 at 4:15 am

    It will be of type XmlNodeType.Text. Not knowing your code if you were simply looping through the XmlReader you should get the following node types (ignoring XmlNodeType.Whitespace). You should get the following nodes

    • Element ()
    • Text (content1content..)
    • Element ()
    • Text (titlex)
    • EndElement ()
    • Text (XXXXX….)
    • Element ()
    • Text (ZZZZ…)
    • EndElement ()
    • EndElemnt (/xhtml:li>)

    When the NodeType of your reader is of type text you can use the Value property to retrieve the text.

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