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Home/ Questions/Q 212581
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Editorial Team
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Editorial Team
Asked: May 11, 20262026-05-11T18:12:00+00:00 2026-05-11T18:12:00+00:00

XML: <A><B></B></A> or <A></A> I want to get all A nodes that do not

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XML: <A><B></B></A> or <A></A>

I want to get all A nodes that do not have any B children.

I’ve tried

/A[not(B)]  
/A[not(exists(B))]

without success

I prefer a solution with the syntax /*[local-name()="A" and .... ], if possible. Any ideas that works?

Clarification. The xml looks like:

<WhatEver>
  <A>
    <B></B>
  </A>
</WhatEver> 

or

<WhatEver>
  <A></A>
</WhatEver>
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-11T18:12:00+00:00Added an answer on May 11, 2026 at 6:12 pm

    Maybe
    *[local-name() = 'A' and not(descendant::*[local-name() = 'B'])]?

    Also, there should be only one root element, so for /A[...] you’re either getting all your XML back or none. Maybe //A[not(B)] or /*/A[not(B)]?

    I don’t really understand why /A[not(B)] doesn’t work for you.

    ~/xml% xmllint ab.xml
    <?xml version="1.0"?>
    <root>
        <A id="1">
                <B/>
        </A>
        <A id="2">
        </A>
        <A id="3">
                <B/>
                <B/>
        </A>
        <A id="4"/>
    </root>
    ~/xml% xpath ab.xml '/root/A[not(B)]'
    Found 2 nodes:
    -- NODE --
    <A id="2">
        </A>
    -- NODE --
    <A id="4" />
    
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