Question

XML

<swift>
 <message>
     <block2 type="input">
        <messageType>102</messageType>
        <receiverAddress>BKTRUS33XBRD</receiverAddress>
        <messagePriority>N</messagePriority>     
     </block2>
     <block3>
     <tag>
     <name>32</name>
     <value>praveen</value>
     </tag>
     <tag>
     <name>42</name>
     <value>pubby</value>
     </tag>
     </block3> 
     <block4>
     <tag>
     <name>77</name>
     <value>pravz</value>
     </tag>
     <tag>
     <name>77</name>
     <value>pubbypravz</value>
     </tag>
     <tag>
     <name>99</name>
     <value>USA</value>
     </tag>
     <tag>
     <name>99</name>
     <value>UK</value>
     </tag>
     <tag>
     <name>76</name>
     <value>shanmu</value>
     </tag>
  </block4>
 </message>
</swift>

XSL

      <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">

          <xsl:output method="text" />
           <xsl:param name="count" select="000001"></xsl:param >
            <xsl:template match="/">
             <xsl:for-each select ="swift/message">

             <xsl:variable name="newtype">
        <xsl:choose>
        <xsl:when test="block2[@type = 'input']">

     <xsl:value-of  select=" concat('O', block2/messageType,block2/messagePriority )"/>,<xsl:text/>
            </xsl:when>

            <xsl:when test="block2[@type = 'output']">
     <xsl:value-of  select=" concat('I', block2/messageType,block2/messagePriority )"/>,<xsl:text/>
        </xsl:when>
           </xsl:choose>
            </xsl:variable>

    <xsl:for-each select ="/swift/message/block3/tag[name='32']">
    <xsl:variable name = "first-val" select="value"/>

    <xsl:for-each select ="/swift/message/block4/tag[name='77']">
    <xsl:value-of select="concat($count,',',$first-val, ',',value)"/>

    <xsl:text>
        </xsl:text>
         </xsl:for-each>
       </xsl:for-each>
    </xsl:for-each>
    </xsl:template>
</xsl:stylesheet>

i need to copy the data of which were i have declared name of “newtype” required the data should print in place of this bellow line

  <xsl:value-of select="concat($newtype,',',$first-val, ',',value)"/>

but above which was showing wrong because variable name was declared out of the scope so can any modify make me to reach that ouput please

the above i have hot coded this value 000001 but needed increment for every record

Expected Output

O102N,000001,praveen,pravz,USA

O102N,000002, praveen,pubbypravz,UK

Answer 1

Can you show me your input xml and desired output xml?

I kind of cringe a little when I see a foreach in xsl – it’s a template language, and rarely needs foreach…

<?xml version="1.0" encoding="utf-8"?>
<!DOCTYPE stylesheet [
    <!ENTITY comma "<xsl:text>,</xsl:text>">
    <!ENTITY cr "<xsl:text>
</xsl:text>">
]>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
    xmlns:msxsl="urn:schemas-microsoft-com:xslt" exclude-result-prefixes="msxsl"
>
    <xsl:output method="text" indent="no" />
    <xsl:template match="/">
        <xsl:apply-templates select="/swift/message/block4/tag [name='77']"/>
    </xsl:template>

    <xsl:template match="message/block4/tag [name='77']">
        <xsl:apply-templates select="../../block2/@type"/>
        <xsl:value-of select="../../block2/messageType"/>
        <xsl:value-of select="../../block2/messagePriority"/>&comma;
        <xsl:number format="000001"/>&comma;
        <xsl:value-of select="../../block3/tag [name='32']/value"/>&comma;
        <xsl:value-of select="value"/>&cr;
    </xsl:template>

    <xsl:template match="@type[.='input']">O</xsl:template>

    <xsl:template match="@type[.='output']">I</xsl:template>

    <xsl:template match="text()"/>

</xsl:stylesheet>

You need one row for each block4 name. So apply a template for that block4/tag [name=’77’]

Then – for every one of those, select the parent elements that you need.

xsl:number will count the number of times it selected.

The ENTITY items are there to control whitespace – otherwise the formatting is crap.

No need for a foreach. Hope this helps