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Editorial Team
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Asked: 2026-06-15T07:14:25+00:00

XML Version 1 <inboundData xmlns=urn:college:names:ws:docexchange> <Root> <College Version=5.0 xmlns:cidx=urn:abc:names:specification:col:schema:all:5:0 xmlns=urn:abc:names:specification:col:schema:all:5:0> <Header> <Address> <AddressLine1>4600 Big

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XML Version 1 

<inboundData xmlns="urn:college:names:ws:docexchange">
<Root>
        <College Version="5.0" xmlns:cidx="urn:abc:names:specification:col:schema:all:5:0" xmlns="urn:abc:names:specification:col:schema:all:5:0">
           <Header>
              <Address>
                 <AddressLine1>4600 Big Tree Way</AddressLine1>
              </Address>
           </Header>
    </College>
</Root>
</inboundData>

XML Version 2

<inboundData xmlns="urn:college:names:ws:docexchange">
<Root>
        <ns1:College Version="5.0" xmlns:ns1="urn:abc:names:specification:col:schema:all:5:0">
           <ns1:Header>
              <ns1:Address>
                 <ns1:AddressLine1>4600 Big Tree Way</ns1:AddressLine1>
              </ns1:Address>
           </ns1:Header>
    </ns1:College>
</Root>
</inboundData>

XSL Code

<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:a="urn:abc:names:specification:col:schema:all:5:0" xmlns:b="urn:college:names:ws:docexchange">
<xsl:template match="/">
    <xsl:copy-of select="b:inboundData/b:College/*"/>
</xsl:template>
</xsl:stylesheet>

Correction in the XSL code. (Realized the error after reading Hansen’s response)

<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:a="urn:abc:names:specification:col:schema:all:5:0" xmlns:b="urn:college:names:ws:docexchange">
<xsl:template match="/">
    <xsl:copy-of select="b:inboundData/b:Root/*"/>
</xsl:template>
</xsl:stylesheet>

The XSL code works well for XML version 1. Due to the extra namespace “ns1”, it does not work for type 2. How can I make the xsl code work for both these versions? Kindly enlighten me!

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1 Answer

  1. Editorial Team

    You can match elements by their local name, like

    <?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0" 
    xmlns:xsl="http://www.w3.org/1999/XSL/Transform" 
    xmlns:a="urn:abc:names:specification:col:schema:all:5:0" 
    xmlns:b="urn:college:names:ws:docexchange">
  <xsl:template match="/">
    <xsl:copy-of select="b:inboundData/*[local-name()='College']/*"/>
  </xsl:template>
</xsl:stylesheet>
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