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Editorial Team
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Asked: 2026-05-30T16:03:05+00:00

<?xml version=1.0 encoding=UTF-8?> <web-app xmlns=http://java.sun.com/xml/ns/j2ee xmlns:xsi=http://www.w3.org/2001/XMLSchema-instance xsi:schemaLocation=http://java.sun.com/xml/ns/j2ee http://java.sun.com/xml/ns/j2ee/web-app_2_4.xsd version=2.4> <servlet> <servlet-name>InitializationJSP</servlet-name> <jsp-file>/initialization.jsp</jsp-file> <init-param> <param-name>testParam</param-name>

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<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns="http://java.sun.com/xml/ns/j2ee"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://java.sun.com/xml/ns/j2ee http://java.sun.com/xml/ns/j2ee/web-app_2_4.xsd" version="2.4">
<servlet>
  <servlet-name>InitializationJSP</servlet-name>
  <jsp-file>/initialization.jsp</jsp-file>
  <init-param>
    <param-name>testParam</param-name>
    <param-value>hello from web.xml</param-value>
  </init-param>
</servlet>
<servlet-mapping>
  <servlet-name>InitializationJSP</servlet-name>
  <url-pattern>/Initialization</url-pattern>
</servlet-mapping>
</web-app>

initialization.jsp

<html>
<head>
<title>Initialization Parameters and JSP</title>
</head>
<body>
This page has retrieved the following initialization parameter from web.xml:
<br>
<%= pageContext.getServletConfig().getInitParameter("testParam") %>
</body>
</html>

My directory structure is

sample
   Initialization.jsp
   WEB-INF
      web.xml
      classes/
      lib/

Is there any problem? This jsp file is not running when i run this using tomcat and appending /initialization after the application url.

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1 Answer

  1. Editorial Team

    change this
    <jsp-file>/initialization.jsp</jsp-file>
    to
    <jsp-file>/Initialization.jsp</jsp-file>

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