Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • SEARCH
  • Home
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 880475
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: May 15, 20262026-05-15T12:06:17+00:00 2026-05-15T12:06:17+00:00

[XmlRoot(ConfigurationRoot)] public class XmlDBConfiguration { [XmlArray(Customers)] [XmlArrayItem(Customer, typeof(Customer))] public ArrayList _customers; private Dictionary<string, Customer>

  • 0
[XmlRoot("ConfigurationRoot")]
public class XmlDBConfiguration
{
    [XmlArray("Customers")]
    [XmlArrayItem("Customer", typeof(Customer))]

    public ArrayList _customers;
    private Dictionary<string, Customer> _customerDictionary;}

Is it possible to define the Element Name (in my case it is ConfigurationRoot) with a variable from another static class or any other way? I want to define my class that is going to be serialized (in my case it is Customer) as well. Is it possible to put a variable there and change it when I create an instance of that ?

Thanks in advance

  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-05-15T12:06:18+00:00Added an answer on May 15, 2026 at 12:06 pm

    I don’t think you can change the value of the XmlRoot attribute on your class. You can however specify an override of this attribute when you create XmlSerializer – just use this constructor: http://msdn.microsoft.com/en-us/library/f1wczcys.aspx

    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Ask A Question

Stats

  • Questions 502k
  • Answers 502k
  • Best Answers 0
  • User 1
  • Popular
  • Answers
  • Editorial Team

    How to approach applying for a job at a company ...

    • 7 Answers
  • Editorial Team

    What is a programmer’s life like?

    • 5 Answers
  • Editorial Team

    How to handle personal stress caused by utterly incompetent and ...

    • 5 Answers
  • Editorial Team
    Editorial Team added an answer A good introduction to asp.net MVC is the 1st chapter… May 16, 2026 at 2:39 pm
  • Editorial Team
    Editorial Team added an answer Server.MapPath takes an application relative path (beginning with a ~)… May 16, 2026 at 2:39 pm
  • Editorial Team
    Editorial Team added an answer If using Apache, mod_rewrite can solve this: RewriteEngine on RewriteRule… May 16, 2026 at 2:39 pm

Trending Tags

analytics british company computer developers django employee employer english facebook french google interview javascript language life php programmer programs salary

Top Members

Related Questions

I've got a class like this: [XmlRoot(channel)] public class Channel { [XmlElement(title)] public String
I have a class Image implementing ISerializable : [Serializable] [XmlRoot(ElementName = IMAGE)] [TypeConverter(typeof(ImageTypeConverter))] public
Here is the code: [XmlRoot(Foo)] class Foo { [XmlElement(name)] string name; } [XmlRoot(FooContainer)] class
I have the following class [XmlRoot(ElementName= webSites)] //No capital w at the beginning public
I have the following classes [XmlRoot] public class AList { public List<B> ListOfBs {get;
Assume I have a C# class like this: [XmlRoot(floors)] public class FloorCollection { [XmlElement(floor)]
I have the following class: [Serializable] [XmlRoot ( ElementName = TextData, IsNullable = false)]
I have a class PersonList [XmlRoot(Persons)] PersonList : List<Human> when I serialize this to
Here's the class im trying to store [Serializable] [XmlRoot(ElementName = Database, IsNullable = false,
In a project I am working on, I just finished writing an XSD for

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.