Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • Home
  • SEARCH
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 34925
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: May 10, 20262026-05-10T14:09:18+00:00 2026-05-10T14:09:18+00:00

<xsl:for-each select=./node [position() &lt;= (count(*) div 2)]> <li>foo</li> </xsl:for-each> <xsl:for-each select=./node [count(*) div 2

  • 0
<xsl:for-each select='./node [position() &lt;= (count(*) div 2)]'>     <li>foo</li> </xsl:for-each> <xsl:for-each select='./node [count(*) div 2 &lt; position()]'>     <li>bar</li> </xsl:for-each> 

My list has 12 nodes, but the second list is always 8 and the first is always 4. What’s wrong with my selects?

  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. 2026-05-10T14:09:18+00:00Added an answer on May 10, 2026 at 2:09 pm

    When you do count(*), the current node is the node element being processed. You want either count(current()/node) or last() (preferable), or just calculate the midpoint to a variable for better performance and clearer code:

    <xsl:variable name='nodes' select='node'/> <xsl:variable name='mid' select='count($nodes) div 2'/> <xsl:for-each select='$nodes[position() &lt;= $mid]'>   <li>foo</li> </xsl:for-each> <xsl:for-each select='$nodes[$mid &lt; position()]'>   <li>bar</li> </xsl:for-each> 
    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Related Questions

I have nested xsl:for loops: <xsl:for-each select=/Root/A> <xsl:for-each select=/Root/B> <!-- Code --> </xsl:for> </xsl:for>
How to get a counter inside xsl:for-each loop that would reflect the number of
How do I save the iterations that have occurred in an xsl:for-each? (variables in
I was using an XSL style sheet to do the sorting but it seems
Can anyone (maybe an XSL-fan?) help me find any advantages with handling presentation of
I have a xsl file that is grabbing variables from xml and they seem
As a huge XSL fan, I am very happy to use xsl as the
I have the following xsl template that I'm using to group my xsl. The
I have a xslt stylesheet with multiple xsl:import s and I want to merge

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.